C++ 代码:使用最小生成树连接 PLY 点云文件中的点
#include
using namespace std;
// 定义点的数据结构 struct Point { float x, y, z; };
// 定义边的数据结构 struct Edge { int p1, p2; float weight; };
// 定义比较函数 struct Compare { bool operator()(const Edge& e1, const Edge& e2) { return e1.weight > e2.weight; } };
// 读取PLY文件,返回点云数据
vector
ifstream file(filename, ios::in);
string line;
// 读取头部信息
while (getline(file, line)) {
if (line == "end_header") {
break;
}
}
// 读取点数据
while (getline(file, line)) {
Point p;
sscanf(line.c_str(), "%f %f %f", &p.x, &p.y, &p.z);
points.push_back(p);
}
file.close();
return points;
}
// 计算两个点之间的距离 float distance(const Point& p1, const Point& p2) { float dx = p1.x - p2.x; float dy = p1.y - p2.y; float dz = p1.z - p2.z; return sqrt(dx * dx + dy * dy + dz * dz); }
// 计算最小生成树,返回边的集合
vector
// 构建边的集合
for (int i = 0; i < n - 1; ++i) {
for (int j = i + 1; j < n; ++j) {
Edge e;
e.p1 = i;
e.p2 = j;
e.weight = distance(points[i], points[j]);
pq.push(e);
}
}
// 计算最小生成树
vector<int> parent(n);
for (int i = 0; i < n; ++i) {
parent[i] = i;
}
int count = 0;
while (count < n - 1 && !pq.empty()) {
Edge e = pq.top();
pq.pop();
int p1 = e.p1;
int p2 = e.p2;
int parent1 = parent[p1];
int parent2 = parent[p2];
while (parent1 != parent[parent1]) {
parent1 = parent[parent1];
}
while (parent2 != parent[parent2]) {
parent2 = parent[parent2];
}
if (parent1 != parent2) {
edges.push_back(e);
++count;
parent[parent1] = parent2;
}
}
return edges;
}
// 将点云数据和边的集合输出为PLY文件
void writePLY(const char* filename, const vector
// 将边的集合转换为线段集合
vector<pair<Point, Point>> edgesToSegments(const vector
int main(int argc, char** argv) {
// 读取PLY文件
vector
// 计算最小生成树
vector<Edge> edges = minimumSpanningTree(points);
// 将点云数据和边的集合输出为PLY文件
writePLY("output.ply", points, edges);
// 将边的集合转换为线段集合
vector<pair<Point, Point>> segments = edgesToSegments(points, edges);
// 输出线段集合
for (const auto& segment : segments) {
cout << "(" << segment.first.x << ", " << segment.first.y << ", " << segment.first.z << ") - ";
cout << "(" << segment.second.x << ", " << segment.second.y << ", " << segment.second.z << ")" << endl;
}
return 0;
}
原文地址: https://www.cveoy.top/t/topic/nRdx 著作权归作者所有。请勿转载和采集!