ROS C++ 代码实现乌龟等边三角形编队
以下是实现代码,其中包含了键盘控制 A 运动的部分和保持编队的部分:
#include <ros/ros.h>
#include <geometry_msgs/Twist.h>
#include <turtlesim/Pose.h>
#include <cmath>
#define PI 3.14159265
ros::Publisher turtleA_pub, turtleB_pub, turtleC_pub;
ros::Subscriber turtleA_sub;
turtlesim::Pose turtleA_pose, turtleB_pose, turtleC_pose;
void turtleA_pose_callback(const turtlesim::Pose::ConstPtr& msg) {
turtleA_pose = *msg;
}
void move_turtleA(double speed, double distance, bool isForward) {
geometry_msgs::Twist turtleA_msg;
turtleA_msg.linear.x = isForward ? speed : -speed;
turtleA_msg.linear.y = 0;
turtleA_msg.linear.z = 0;
turtleA_msg.angular.x = 0;
turtleA_msg.angular.y = 0;
turtleA_msg.angular.z = 0;
double t0 = ros::Time::now().toSec();
double current_distance = 0;
ros::Rate loop_rate(10);
while (current_distance < distance) {
turtleA_pub.publish(turtleA_msg);
double t1 = ros::Time::now().toSec();
current_distance = speed * (t1 - t0);
ros::spinOnce();
loop_rate.sleep();
}
turtleA_msg.linear.x = 0;
turtleA_pub.publish(turtleA_msg);
}
void move_turtleB(double speed, double distance, bool isForward) {
geometry_msgs::Twist turtleB_msg;
turtleB_msg.linear.x = isForward ? speed : -speed;
turtleB_msg.linear.y = 0;
turtleB_msg.linear.z = 0;
turtleB_msg.angular.x = 0;
turtleB_msg.angular.y = 0;
turtleB_msg.angular.z = 0;
double t0 = ros::Time::now().toSec();
double current_distance = 0;
ros::Rate loop_rate(10);
while (current_distance < distance) {
turtleB_pub.publish(turtleB_msg);
double t1 = ros::Time::now().toSec();
current_distance = speed * (t1 - t0);
ros::spinOnce();
loop_rate.sleep();
}
turtleB_msg.linear.x = 0;
turtleB_pub.publish(turtleB_msg);
}
void move_turtleC(double speed, double distance, bool isForward) {
geometry_msgs::Twist turtleC_msg;
turtleC_msg.linear.x = isForward ? speed : -speed;
turtleC_msg.linear.y = 0;
turtleC_msg.linear.z = 0;
turtleC_msg.angular.x = 0;
turtleC_msg.angular.y = 0;
turtleC_msg.angular.z = 0;
double t0 = ros::Time::now().toSec();
double current_distance = 0;
ros::Rate loop_rate(10);
while (current_distance < distance) {
turtleC_pub.publish(turtleC_msg);
double t1 = ros::Time::now().toSec();
current_distance = speed * (t1 - t0);
ros::spinOnce();
loop_rate.sleep();
}
turtleC_msg.linear.x = 0;
turtleC_pub.publish(turtleC_msg);
}
void move_turtles(double speed, double distance, bool isForward) {
move_turtleA(speed, distance, isForward);
move_turtleB(speed, distance, isForward);
move_turtleC(speed, distance, isForward);
}
void rotate_turtles(double angular_speed, double angle, bool clockwise) {
geometry_msgs::Twist turtleA_msg, turtleB_msg, turtleC_msg;
turtleA_msg.linear.x = 0;
turtleA_msg.linear.y = 0;
turtleA_msg.linear.z = 0;
turtleA_msg.angular.x = 0;
turtleA_msg.angular.y = 0;
turtleA_msg.angular.z = clockwise ? -abs(angular_speed) : abs(angular_speed);
turtleB_msg.linear.x = 0;
turtleB_msg.linear.y = 0;
turtleB_msg.linear.z = 0;
turtleB_msg.angular.x = 0;
turtleB_msg.angular.y = 0;
turtleB_msg.angular.z = clockwise ? -abs(angular_speed) : abs(angular_speed);
turtleC_msg.linear.x = 0;
turtleC_msg.linear.y = 0;
turtleC_msg.linear.z = 0;
turtleC_msg.angular.x = 0;
turtleC_msg.angular.y = 0;
turtleC_msg.angular.z = clockwise ? -abs(angular_speed) : abs(angular_speed);
double t0 = ros::Time::now().toSec();
double current_angle = 0;
ros::Rate loop_rate(10);
while (current_angle < angle) {
turtleA_pub.publish(turtleA_msg);
turtleB_pub.publish(turtleB_msg);
turtleC_pub.publish(turtleC_msg);
double t1 = ros::Time::now().toSec();
current_angle = angular_speed * (t1 - t0);
ros::spinOnce();
loop_rate.sleep();
}
turtleA_msg.angular.z = 0;
turtleB_msg.angular.z = 0;
turtleC_msg.angular.z = 0;
turtleA_pub.publish(turtleA_msg);
turtleB_pub.publish(turtleB_msg);
turtleC_pub.publish(turtleC_msg);
}
int main(int argc, char** argv) {
ros::init(argc, argv, 'turtle_triangle');
ros::NodeHandle node;
turtleA_pub = node.advertise<geometry_msgs::Twist>('/turtle1/cmd_vel', 10);
turtleB_pub = node.advertise<geometry_msgs::Twist>('/turtle2/cmd_vel', 10);
turtleC_pub = node.advertise<geometry_msgs::Twist>('/turtle3/cmd_vel', 10);
turtleA_sub = node.subscribe('/turtle1/pose', 10, turtleA_pose_callback);
ros::Rate loop_rate(10);
// Move turtles to initial positions
move_turtles(1.0, 2.0, true);
rotate_turtles(PI/2, PI/2, false);
move_turtles(1.0, 2.0, true);
rotate_turtles(-PI/3, PI/3, true);
while (ros::ok()) {
// Get keyboard input
char input;
std::cin >> input;
switch (input) {
case 'w':
move_turtleA(1.0, 1.0, true);
move_turtles(1.0, sqrt(3), true);
break;
case 'a':
rotate_turtles(PI/3, PI/3, true);
move_turtleA(1.0, 1.0, true);
move_turtles(1.0, sqrt(3), true);
break;
case 's':
move_turtleA(1.0, 1.0, false);
move_turtles(1.0, sqrt(3), false);
break;
case 'd':
rotate_turtles(-PI/3, PI/3, false);
move_turtleA(1.0, 1.0, true);
move_turtles(1.0, sqrt(3), true);
break;
default:
break;
}
ros::spinOnce();
loop_rate.sleep();
}
return 0;
}
在代码中,首先定义了三个 Publisher 和一个 Subscriber,分别用于控制三只乌龟的运动和获取 A 乌龟的位置信息。然后定义了一些函数,包括了移动和旋转三只乌龟的函数,以及移动三只乌龟到初始位置的函数。
在主函数中,首先移动三只乌龟到初始位置,然后进入循环中。循环中通过读取键盘输入来控制 A 乌龟的运动,然后调用移动和旋转函数来保持编队。循环中还包含了 ROS 的 spinOnce() 和 sleep() 函数,用于处理 ROS 的回调函数和控制运行频率。
需要注意的是,由于键盘输入的阻塞特性,需要在终端中按下回车键才能执行下一个键盘输入。
原文地址: https://www.cveoy.top/t/topic/jo0s 著作权归作者所有。请勿转载和采集!