ROS C++ 代码实现乌龟编队:等边三角形运动
以下是实现该功能的 ROS C++ 代码:
#include <ros/ros.h>
#include <geometry_msgs/Twist.h>
#include <turtlesim/Pose.h>
#include <cmath>
// 三只乌龟的全局变量
turtlesim::Pose turtleA_pose;
turtlesim::Pose turtleB_pose;
turtlesim::Pose turtleC_pose;
// 计算两点之间的距离
float distance(float x1, float y1, float x2, float y2)
{
return std::sqrt(std::pow(x1 - x2, 2) + std::pow(y1 - y2, 2));
}
// 计算两点之间的角度
float angle(float x1, float y1, float x2, float y2)
{
return std::atan2(y2 - y1, x2 - x1);
}
// 乌龟A的回调函数
void turtleA_callback(const turtlesim::Pose::ConstPtr& pose_msg)
{
turtleA_pose = *pose_msg;
// 计算乌龟B和乌龟C的位置
float xB = turtleA_pose.x + std::cos(turtleA_pose.theta + M_PI / 3);
float yB = turtleA_pose.y + std::sin(turtleA_pose.theta + M_PI / 3);
float xC = turtleA_pose.x + std::cos(turtleA_pose.theta - M_PI / 3);
float yC = turtleA_pose.y + std::sin(turtleA_pose.theta - M_PI / 3);
// 发布速度控制指令
ros::NodeHandle nh;
ros::Publisher turtleB_vel_pub = nh.advertise<geometry_msgs::Twist>("/turtle2/cmd_vel", 10);
ros::Publisher turtleC_vel_pub = nh.advertise<geometry_msgs::Twist>("/turtle3/cmd_vel", 10);
geometry_msgs::Twist vel_msg;
// 计算乌龟B和乌龟C需要前进的距离和旋转的角度
float distanceB = distance(turtleB_pose.x, turtleB_pose.y, xB, yB);
float distanceC = distance(turtleC_pose.x, turtleC_pose.y, xC, yC);
float angleB = angle(turtleB_pose.x, turtleB_pose.y, xB, yB) - turtleB_pose.theta;
float angleC = angle(turtleC_pose.x, turtleC_pose.y, xC, yC) - turtleC_pose.theta;
// 发布速度控制指令使乌龟B和乌龟C前进和旋转
vel_msg.linear.x = distanceB;
vel_msg.angular.z = angleB;
turtleB_vel_pub.publish(vel_msg);
vel_msg.linear.x = distanceC;
vel_msg.angular.z = angleC;
turtleC_vel_pub.publish(vel_msg);
}
// 乌龟B的回调函数
void turtleB_callback(const turtlesim::Pose::ConstPtr& pose_msg)
{
turtleB_pose = *pose_msg;
}
// 乌龟C的回调函数
void turtleC_callback(const turtlesim::Pose::ConstPtr& pose_msg)
{
turtleC_pose = *pose_msg;
}
int main(int argc, char** argv)
{
ros::init(argc, argv, "turtle_triangle");
ros::NodeHandle nh;
// 订阅乌龟A、B、C的位置信息
ros::Subscriber turtleA_sub = nh.subscribe("/turtle1/pose", 10, turtleA_callback);
ros::Subscriber turtleB_sub = nh.subscribe("/turtle2/pose", 10, turtleB_callback);
ros::Subscriber turtleC_sub = nh.subscribe("/turtle3/pose", 10, turtleC_callback);
// 控制乌龟A运动
ros::Publisher turtleA_vel_pub = nh.advertise<geometry_msgs::Twist>("/turtle1/cmd_vel", 10);
geometry_msgs::Twist vel_msg;
while (ros::ok())
{
// 读取键盘输入
char c;
std::cout << "Enter a key: ";
std::cin >> c;
// 根据键盘输入计算速度控制指令
switch (c)
{
case 'w':
vel_msg.linear.x = 1;
vel_msg.angular.z = 0;
break;
case 'a':
vel_msg.linear.x = 0;
vel_msg.angular.z = 1;
break;
case 's':
vel_msg.linear.x = -1;
vel_msg.angular.z = 0;
break;
case 'd':
vel_msg.linear.x = 0;
vel_msg.angular.z = -1;
break;
default:
vel_msg.linear.x = 0;
vel_msg.angular.z = 0;
break;
}
// 发布速度控制指令
turtleA_vel_pub.publish(vel_msg);
// 循环等待回调函数
ros::spinOnce();
}
return 0;
}
该代码中,我们订阅了三只乌龟的位置信息,并在乌龟A的回调函数中计算出乌龟B和乌龟C需要前进和旋转的距离和角度,然后通过发布速度控制指令使乌龟B和乌龟C移动和旋转。在主循环中,我们通过读取键盘输入来控制乌龟A的运动,并通过发布速度控制指令来实现。
原文地址: https://www.cveoy.top/t/topic/jo0g 著作权归作者所有。请勿转载和采集!