The error message "TypeError: issubclass() arg 1 must be a class" is raised when the argument passed to the issubclass() function is not a class. The issubclass() function is used to check if a class is a subclass of another class.

To resolve this error, make sure that the argument passed to issubclass() is a valid class. Here's an example of correct usage:

class MyClass:
    pass

class MySubClass(MyClass):
    pass

print(issubclass(MySubClass, MyClass))  # Output: True

In this example, MySubClass is a subclass of MyClass, so issubclass(MySubClass, MyClass) returns True

typingpy TypeError issubclass arg 1 must be a class

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