用vbnet写一个函数根据若干个点坐标XYZ运用最小二乘法计算平面度的函数
以下是用VB.NET写的根据若干个点坐标XYZ运用最小二乘法计算平面度的函数:
Public Function CalculateFlatness(points As List(Of Point3D)) As Double
'计算平面度
Dim n As Integer = points.Count
Dim sumX As Double = 0
Dim sumY As Double = 0
Dim sumZ As Double = 0
Dim sumX2 As Double = 0
Dim sumY2 As Double = 0
Dim sumXY As Double = 0
Dim sumXZ As Double = 0
Dim sumYZ As Double = 0
For i = 0 To n - 1
Dim point As Point3D = points(i)
sumX += point.X
sumY += point.Y
sumZ += point.Z
sumX2 += point.X ^ 2
sumY2 += point.Y ^ 2
sumXY += point.X * point.Y
sumXZ += point.X * point.Z
sumYZ += point.Y * point.Z
Next
Dim matrix(,) As Double = {{n, sumX, sumY},
{sumX, sumX2, sumXY},
{sumY, sumXY, sumY2}}
Dim b() As Double = {sumZ, sumXZ, sumYZ}
Dim coefficients() As Double = Solve(matrix, b)
Dim a As Double = coefficients(0)
Dim b1 As Double = coefficients(1)
Dim b2 As Double = coefficients(2)
Dim flatness As Double = Math.Sqrt(b1 ^ 2 + b2 ^ 2 + 1)
Return flatness
End Function
Private Function Solve(A As Double(,), B As Double()) As Double()
Dim n As Integer = B.Length
Dim X(n - 1) As Double
For i = 0 To n - 2
For j = i + 1 To n - 1
Dim factor As Double = A(j, i) / A(i, i)
For k = i To n - 1
A(j, k) -= factor * A(i, k)
Next
B(j) -= factor * B(i)
Next
Next
For i = n - 1 To 0 Step -1
For j = i + 1 To n - 1
B(i) -= A(i, j) * X(j)
Next
X(i) = B(i) / A(i, i)
Next
Return X
End Function
该函数接受一个List(Of Point3D)类型参数,表示若干个点的坐标,其中Point3D类型包含X、Y、Z三个属性,分别表示点的x、y、z坐标。
函数通过最小二乘法计算出平面的方程,即Z = a + b1 * X + b2 * Y,然后计算出平面度,即sqrt(b1 ^ 2 + b2 ^ 2 + 1),最后返回平面度
原文地址: https://www.cveoy.top/t/topic/hblC 著作权归作者所有。请勿转载和采集!