class Solution public int searchInsertvectorint& nums int target int n = numssize; int left = 0 right = n - 1 ans = n; while left = right int mid = right - left 1

This is a solution to the "Search Insert Position" problem on LeetCode.

The problem asks us to find the index of the target element in a sorted array, or the index where it should be inserted if it is not present in the array.

The solution uses a binary search algorithm to find the index. It initializes two pointers, left and right, to the first and last indices of the array. It also initializes a variable ans to n, which represents the index where the target should be inserted if it is not present in the array.

The algorithm then enters a while loop that continues as long as left is less than or equal to right. Inside the loop, it calculates the midpoint of the current range using the bitwise right shift operator and adds the result to the left pointer. If the target is less than or equal to the element at the midpoint, it updates ans to the midpoint and sets the right pointer to the element to the left of the midpoint. Otherwise, it sets the left pointer to the element to the right of the midpoint.

Once the while loop terminates, the function returns the value of ans, which contains either the index of the target element or the index where it should be inserted.

Overall, this solution has a time complexity of O(log n) and a space complexity of O(1), since it only uses a constant amount of extra space to store variables