Let's assume that there are 'x' billboards in front of the car when it stops. According to the given conditions, we have the inequality: 12 + 27(x - 1) ≤ 320 + 19. Solving this inequality, we get x ≤ 13 1/9. Therefore, when the car stops, there are 13 billboards in front of it, and it is 3 kilometers past the 13th billboard. Hence, the distance between the last billboard the car passes and location A before stopping is 320 + 19 - 3 = 336 kilometers. Therefore, the correct answer is D.

How many billboards does a car pass before stopping? - Detailed Solution

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