用C++实现类似Python的简单编程语言:语法解析与代码生成
以下是使用C++截取字符串的方式实现一门简单编程语言的示例代码:
#include <iostream>
#include <fstream>
#include <string>
int main() {
std::string code = R"(
def add(a, b):
return a + b
result = add(3, 5)
print(result)
)";
std::ofstream outputFile("code.cpp");
if (outputFile.is_open()) {
outputFile << R"(#include <iostream>
int add(int a, int b) {
return a + b;
}
int main() {
)";
std::size_t pos = 0;
std::string delimiter = "\n";
std::string line;
while ((pos = code.find(delimiter)) != std::string::npos) {
line = code.substr(0, pos);
code.erase(0, pos + delimiter.length());
if (line.find("def") != std::string::npos) {
// Function definition
std::size_t startPos = line.find("def") + 4;
std::size_t endPos = line.find("(");
std::string functionName = line.substr(startPos, endPos - startPos);
std::size_t colonPos = line.find(":");
std::string returnType = line.substr(colonPos + 1);
std::string functionBody = "";
std::string indentation = " ";
std::string functionParams = line.substr(endPos + 1, colonPos - endPos - 1);
std::string params = "";
std::size_t commaPos = 0;
while ((commaPos = functionParams.find(",")) != std::string::npos) {
std::string param = functionParams.substr(0, commaPos);
params += "int " + param + ", ";
functionParams.erase(0, commaPos + 2);
}
params += "int " + functionParams;
outputFile << indentation << returnType << " " << functionName << "(" << params << ") {
";
while (code.find(indentation) == 0) {
std::size_t newLinePos = code.find("\n");
std::string statement = code.substr(indentation.length(), newLinePos - indentation.length());
code.erase(0, newLinePos + 1);
outputFile << indentation << statement << "\n";
}
outputFile << "}
\n";
}
else if (line.find("=") != std::string::npos) {
// Variable assignment
std::size_t equalsPos = line.find("=");
std::string variableName = line.substr(0, equalsPos);
std::string variableValue = line.substr(equalsPos + 1);
outputFile << "int " << variableName << " = " << variableValue << ";\n";
}
else if (line.find("print") != std::string::npos) {
// Print statement
std::size_t openParenPos = line.find("(");
std::size_t closeParenPos = line.find(")");
std::string printValue = line.substr(openParenPos + 1, closeParenPos - openParenPos - 1);
outputFile << "std::cout << " << printValue << " << std::endl;\n";
}
}
outputFile << R"(
return 0;
}
)";
outputFile.close();
std::cout << "C++ code generated successfully!" << std::endl;
}
else {
std::cerr << "Failed to open output file." << std::endl;
return 1;
}
return 0;
}
使用方法:
- 将要转换的代码放入
code字符串中。 - 运行上述代码,它将生成名为
code.cpp的C++代码文件。 - 编译和运行
code.cpp文件即可得到相应的输出。
注意事项:
- 目前仅支持整数类型。
- 代码转换的规则仅适用于给定的示例代码,如果需要支持更多的语法或数据类型,请相应地修改代码转换的逻辑。
- 请确保C++编译器已正确安装并设置好环境变量。
原文地址: https://www.cveoy.top/t/topic/u9W 著作权归作者所有。请勿转载和采集!