C语言计算1到131数字中个位、十位、百位出现次数

#include <stdio.h>

int countOnes(int num) { int count = 0; while (num > 0) { if (num % 10 == 1) count++; num /= 10; } return count; }

int main() { int onesDigitCount = 0, tensDigitCount = 0, hundredsDigitCount = 0;

for (int num = 1; num <= 131; num++) {
    onesDigitCount += countOnes(num);
    
    int tensDigit = num / 10 % 10;
    if (tensDigit == 1)
        tensDigitCount++;
    
    int hundredsDigit = num / 100;
    if (hundredsDigit == 1)
        hundredsDigitCount++;
}

printf('Ones digit count: %d\n', onesDigitCount);
printf('Tens digit count: %d\n', tensDigitCount);
printf('Hundreds digit count: %d\n', hundredsDigitCount);

return 0;

}