C++递归函数计算结果：m=4, n=4时的返回值

{/'title/':/'请为我计算此段代码在m=4 n=4的结果：//n///'double a(int m,int n)//n/{//n//t if(m==1&&n==0) return 2;//n//n//t else if(m==0&&n>=0) return 1;//n//n//t else if(m>=2&&n==0) return m+2;//n//n//t else return a(a(m-1,n),n-1);//n/}//n///'/',/'description/':/'根据给定的代码，我们可以使用递归的方式计算结果。//n//n首先，我们将 m=4，n=4 代入函数中：//na(4, 4) = a(a(3, 4), 3)//n//n然后，我们继续计算内部的递归：//na(3, 4) = a(a(2, 4), 3)//na(2, 4) = a(a(1, 4), 3)//n//n接下来，我们可以计算 a(1, 4)：//na(1, 4) = a(a(0, 4), 3)//na(0, 4) = 1//n//n因此，我们可以代入计算 a(1, 4)：//na(1, 4) = a(1, 3) = a(a(0, 3), 2) = a(1, 2) = a(a(0, 2), 1) = a(1, 1) = a(a(0, 1), 0) = a(1, 0) = m + 2 = 4 + 2 = 6//n//n接着，我们计算 a(2, 4)：//na(2, 4) = a(6, 3) = a(a(5, 3), 2) = a(8, 2) = a(a(7, 2), 1) = a(10, 1) = a(a(9, 1), 0) = a(11, 0) = 11 + 2 = 13//n//n最后，我们计算 a(3, 4)：//na(3, 4) = a(13, 3) = a(a(12, 3), 2) = a(15, 2) = a(a(14, 2), 1) = a(17, 1) = a(a(16, 1), 0) = a(18, 0) = 18 + 2 = 20//n//n最终，我们可以计算 a(4, 4)：//na(4, 4) = a(20, 3) = a(a(19, 3), 2) = a(22, 2) = a(a(21, 2), 1) = a(24, 1) = a(a(23, 1), 0) = a(25, 0) = 25 + 2 = 27//n//n所以，当 m=4，n=4 时，函数的返回值为 27。/',/'keywords/':/'C++, 递归函数, 递归, 计算, 返回值, m=4, n=4/'}