C++ 购买小狗和小猫方案数量计算 - 算法题

#include "iostream"\nusing namespace std;\n\nint main() {\n int X, A, B;\n cin >> X >> A >> B;\n\n int count = 0;\n for (int i = 1; i < X; i++) {\n int j = X - i;\n if (i % A == 0 && j % B == 0) {\n count++;\n }\n }\n\n cout << count << endl;\n\n return 0;\n}