C++ 找出1-999中满足条件的数

#include

using namespace std;

bool isMultipleOf3(int num) { int sum = 0; while (num > 0) { sum += num % 10; num /= 10; } return sum % 3 == 0; }

bool hasDigit5(int num) { while (num > 0) { if (num % 10 == 5) return true; num /= 10; } return false; }

int main() { for (int i = 1; i <= 999; i++) { if (isMultipleOf3(i) && hasDigit5(i)) cout << i << endl; } return 0; }