C 函数示例：从 SQLite 数据库获取智能家居状态数据并给出建议

{"title": "设计C函数：\n查看：服务器和客户端连接成功后，查看客户端存储在SQlite智能家居状态表中温度和湿度到的数据。\n信息处理：根据SQlite智能家居状态表中的温度和湿度数据，分析出合理建议。\n带注释内容：c\n#include <stdio.h>\n#include <sqlite3.h>\n\n// 回调函数，用于获取查询结果\nstatic int callback(void *data, int argc, char **argv, char **azColName) {\n for (int i = 0; i < argc; i++) {\n printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");\n }\n return 0;\n}\n\n// 查看客户端存储在SQlite智能家居状态表中温度和湿度数据\nvoid viewData() {\n sqlite3 *db;\n char *zErrMsg = 0;\n int rc;\n\n // 打开数据库连接\n rc = sqlite3_open("smart_home.db", &db);\n if (rc) {\n fprintf(stderr, "Can't open database: %s\n", sqlite3_errmsg(db));\n return;\n }\n\n char *sql = "SELECT temperature, humidity FROM smart_home_table;";\n \n // 执行查询语句\n rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg);\n if (rc != SQLITE_OK) {\n fprintf(stderr, "SQL error: %s\n", zErrMsg);\n sqlite3_free(zErrMsg);\n }\n \n // 关闭数据库连接\n sqlite3_close(db);\n}\n\n// 根据温度和湿度数据分析出合理建议\nvoid analyzeData(int temperature, int humidity) {\n if (temperature < 20) {\n printf("It's too cold. Turn up the heating.\n");\n } else if (temperature > 30) {\n printf("It's too hot. Turn on the air conditioning.\n");\n } else {\n printf("The temperature is within the comfortable range.\n");\n }\n\n if (humidity < 40) {\n printf("The air is too dry. Use a humidifier.\n");\n } else if (humidity > 60) {\n printf("The air is too humid. Use a dehumidifier.\n");\n } else {\n printf("The humidity is within the comfortable range.\n");\n }\n}\n\nint main() {\n // 连接服务器和客户端\n \n // 获取温度和湿度数据\n int temperature = 25;\n int humidity = 50;\n \n // 查看数据\n viewData();\n \n // 分析数据并给出建议\n analyzeData(temperature, humidity);\n \n return 0;\n}\n