C语言程序：求正整数的所有乘积因子

"#include<stdio.h>\n\nvoid printFactors(int n, int factor, int min_factor) {\n if (n == 1) {\n printf("%d\n", factor);\n return;\n }\n \n for (int i = min_factor; i <= n; i++) {\n if (n % i == 0) {\n printFactors(n/i, factori, i);\n }\n }\n}\n\nint main() {\n int num;\n printf("请输入一个正整数：");\n scanf("%d", &num);\n \n if (num <= 0) {\n printf("输入错误，请输入正整数。\n");\n return 0;\n }\n \n printf("所有可能的乘积因子如下：\n");\n printFactors(num, 1, 2);\n \n return 0;\n}\n"测试用例：\n输入：24\n输出：\n所有可能的乘积因子如下：\n124\n212\n38\n46\n226\n234\n2223