C# Revit 二次开发：计算两条直线的最短距离和最近点

///'using Autodesk.Revit.DB;//n//npublic double GetShortestDistanceAndNearestPoint(Line line1, Line line2, out XYZ nearestPointOnLine1, out XYZ nearestPointOnLine2)//n{//n double shortestDistance = double.MaxValue;//n nearestPointOnLine1 = null;//n nearestPointOnLine2 = null;//n//n // 计算两条直线的参数值//n double t1, t2;//n line1.Project(line2.GetEndPoint(0), out t1);//n line2.Project(line1.GetEndPoint(0), out t2);//n//n // 如果两条直线相交，则最短距离为0，且最近点为相交点//n if (t1 >= 0 && t1 <= 1 && t2 >= 0 && t2 <= 1)//n {//n shortestDistance = 0;//n nearestPointOnLine1 = line1.Evaluate(t1, true);//n nearestPointOnLine2 = line2.Evaluate(t2, true);//n }//n else//n {//n // 如果两条直线不相交，则计算最短距离和最近点//n double distance1 = line1.Distance(line2.GetEndPoint(0));//n double distance2 = line1.Distance(line2.GetEndPoint(1));//n double distance3 = line2.Distance(line1.GetEndPoint(0));//n double distance4 = line2.Distance(line1.GetEndPoint(1));//n//n if (distance1 < shortestDistance)//n {//n shortestDistance = distance1;//n nearestPointOnLine1 = line1.GetEndPoint(0);//n nearestPointOnLine2 = line2.GetEndPoint(0);//n }//n//n if (distance2 < shortestDistance)//n {//n shortestDistance = distance2;//n nearestPointOnLine1 = line1.GetEndPoint(0);//n nearestPointOnLine2 = line2.GetEndPoint(1);//n }//n//n if (distance3 < shortestDistance)//n {//n shortestDistance = distance3;//n nearestPointOnLine1 = line1.GetEndPoint(0);//n nearestPointOnLine2 = line2.GetEndPoint(0);//n }//n//n if (distance4 < shortestDistance)//n {//n shortestDistance = distance4;//n nearestPointOnLine1 = line1.GetEndPoint(0);//n nearestPointOnLine2 = line2.GetEndPoint(1);//n }//n }//n//n return shortestDistance;//n}//n//n```//n///'using System;//nusing Autodesk.Revit.DB;//n//n// ... (代码省略)//n//nLine line1 = ...; // 第一条直线//nLine line2 = ...; // 第二条直线//n//nXYZ nearestPointOnLine1, nearestPointOnLine2;//ndouble shortestDistance = GetShortestDistanceAndNearestPoint(line1, line2, out nearestPointOnLine1, out nearestPointOnLine2);//n//n// 输出最短距离和最近点//nConsole.WriteLine(/'最短距离: /' + shortestDistance);//nConsole.WriteLine(/'最近点在第一条直线上的坐标: (/' + nearestPointOnLine1.X + /', /' + nearestPointOnLine1.Y + /', /' + nearestPointOnLine1.Z + /')/');//nConsole.WriteLine(/'最近点在第二条直线上的坐标: (/' + nearestPointOnLine2.X + /', /' + nearestPointOnLine2.Y + /', /' + nearestPointOnLine2.Z + /')/');//n//n// ... (代码省略)//n//n请注意，以上代码仅适用于Revit API中的Line对象，如果要计算其他类型的线段或曲线的最短距离和最近点，可能需要使用不同的方法。//n//n/