当然!下面是一个简单的命令行扫雷游戏的示例代码:

import random

# 创建扫雷游戏棋盘
def create_board(rows, cols, num_mines):
    board = [[0] * cols for _ in range(rows)]
    mines = random.sample(range(rows * cols), num_mines)
    for mine in mines:
        row = mine // cols
        col = mine % cols
        board[row][col] = '*'
        for r in range(row - 1, row + 2):
            for c in range(col - 1, col + 2):
                if 0 <= r < rows and 0 <= c < cols and board[r][c] != '*':
                    board[r][c] += 1
    return board

# 显示棋盘
def display_board(board):
    rows = len(board)
    cols = len(board[0])
    for r in range(rows):
        for c in range(cols):
            print(board[r][c], end=' ')
        print()

# 主游戏循环
def play_game(rows, cols, num_mines):
    board = create_board(rows, cols, num_mines)
    is_game_over = False
    while not is_game_over:
        display_board(board)
        row = int(input('输入行号 (0 - {}): '.format(rows - 1)))
        col = int(input('输入列号 (0 - {}): '.format(cols - 1)))
        if board[row][col] == '*':
            print('你踩到地雷了!游戏结束!')
            is_game_over = True
        else:
            board[row][col] = ' '
            if board[row][col] == 0:
                reveal_zeros(board, row, col)
            if check_win(board):
                print('恭喜你,扫雷成功!')
                is_game_over = True

# 揭示周围的空格
def reveal_zeros(board, row, col):
    rows = len(board)
    cols = len(board[0])
    for r in range(row - 1, row + 2):
        for c in range(col - 1, col + 2):
            if 0 <= r < rows and 0 <= c < cols and board[r][c] == 0:
                board[r][c] = ' '
                reveal_zeros(board, r, c)

# 检查是否胜利
def check_win(board):
    rows = len(board)
    cols = len(board[0])
    for r in range(rows):
        for c in range(cols):
            if board[r][c] != ' ' and board[r][c] != '*':
                return False
    return True

# 运行游戏
play_game(5, 5, 5)

这只是一个简单的示例,你可以根据自己的需要进行定制和扩展。记得在运行代码之前,确保你的Python环境已经安装好。

用Python编写简单的命令行扫雷游戏

原文地址: https://www.cveoy.top/t/topic/plI 著作权归作者所有。请勿转载和采集!

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