前衬套工艺代码相同数据查询
您可以使用以下代码来实现您的需求:
const data = [
{
"del": 0,
"createBy": "GW00303172",
"createTime": "2023-10-16 11:17:16",
"updateBy": "GW00303172",
"updateTime": "2023-10-16 11:17:16",
"id": 2685,
"processId": 1383,
"projectId": 35,
"productCode": "PA 20230905 739d896a58",
"productBomCode": "20230905 11 63d3244aa7",
"materialCode": "PA 20230905 739d896a58",
"materialName": "前衬套",
"electrophoreticArea": 200,
"weldBeadLength": 100,
"roughWeight": 2,
"materialCategory": "2",
"materialType": 0,
"supplierStatus": "1",
"materialStatus": "3",
"importanceLevel": "1",
"sourceFrom": "0",
"yieldCode": null,
"level": 1,
"weight": 1.02,
"specifications": "--",
"borrowRelation": "J65",
"num": 1,
"targetPrice": 66,
"other": "1",
"projectCode": "1",
"materialId": 2685,
"deliveryAddress": "5",
"passRatio": "5",
"craftCode": "GY000105",
"craftSubType": "3",
"type1": "0",
"type2": "0",
"type3": "0",
"productionPlaceCode": "CD0003"
},
{
"rowId": "1697437037701926",
"productCode": "PA 20230905 739d896a58",
"projectCode": "1",
"productBomCode": "20230905 11 63d3244aa7",
"processId": 1383,
"materialCode": "PA 20230905 739d896a58",
"materialName": "前衬套7",
"materialCategory": "2",
"specifications": "--",
"weight": 1.02,
"importanceLevel": "1",
"level": 1,
"sourceFrom": "0",
"materialId": 2685,
"productionPlaceCode": "CD0006",
"deliveryAddress": "6",
"passRatio": "5",
"craftCode": "GY000106",
"craftSubType": "6",
"type1": "0",
"type2": "1",
"type3": "0"
},
// ... 其他数据项
];
const result = {};
for (let i = 0; i < data.length; i++) {
const item = data[i];
if (result[item.materialCode]) {
if (result[item.materialCode][item.craftCode]) {
result[item.materialCode][item.craftCode].push(item);
} else {
result[item.materialCode][item.craftCode] = [item];
}
} else {
result[item.materialCode] = {
[item.craftCode]: [item],
};
}
}
for (const materialCode in result) {
for (const craftCode in result[materialCode]) {
console.log(result[materialCode][craftCode]);
}
}
这段代码会先将数组中相同 materialCode 的数据进行分组,然后再根据 craftCode 进行分组。最后,会打印出每个相同 craftCode 的数据。
原文地址: http://www.cveoy.top/t/topic/pi8M 著作权归作者所有。请勿转载和采集!