Calculating Time for a Horizontally Thrown Ball to Reach the Ground

To solve this problem, we can use the equation of motion for the vertical direction:

$h = \frac{1}{2}gt^2$

Where:

• h is the initial height of the ball (3m)
• g is the acceleration due to gravity (9.8 m/s^2)
• t is the time taken for the ball to reach the ground

For the green ball, since it is thrown horizontally, the initial vertical velocity is 0 m/s. Therefore, the equation becomes:

$h = \frac{1}{2}gt^2$ $3 = \frac{1}{2}(9.8)t^2$ $6 = 9.8t^2$ $t^2 = \frac{6}{9.8}$ $t^2 = 0.6122$ $t = \sqrt{0.6122}$ $t \approx 0.782$ seconds

Therefore, the green ball takes approximately 0.782 seconds to reach the ground relative to the red ball.