Python 代码实现回旋数打印 - 按顺时针递增排列

你好\！你需要一个程序来打印出回旋数\。下面是一个Python程序，可以实现你的需求\：\n\npython\ndef print_spiral(n):\n spiral = [[0] * n for _ in range(n)]\n num = 1\n\n # 定义边界\n top = 0\n bottom = n - 1\n left = 0\n right = n - 1\n\n while num <= n * n:\n # 从左到右\n for i in range(left, right + 1):\n spiral[top][i] = num\n num += 1\n top += 1\n\n # 从上到下\n for i in range(top, bottom + 1):\n spiral[i][right] = num\n num += 1\n right -= 1\n\n # 从右到左\n for i in range(right, left - 1, -1):\n spiral[bottom][i] = num\n num += 1\n bottom -= 1\n\n # 从下到上\n for i in range(bottom, top - 1, -1):\n spiral[i][left] = num\n num += 1\n left += 1\n\n # 打印回旋数\n for row in spiral:\n for num in row:\n print(f"{num:02d}", end=" ")\n print()\n\n# 测试示例\n n = int(input("请输入正方形的行(或列)元素个数n："))\n print_spiral(n)\n\n\n你可以运行这个程序并输入一个整数n来测试\。它将打印出一个正方形的回旋数，数字按顺时针递增排列\。