优化 JavaScript 代码：使用 AJAX 获取数据并更新表单

您可以尝试以下修改：\n\n1. 将 subject_stype 和 subject_scontent 的值改为变量 subject_stype_val 和 subject_scontent_val，以免与表单元素混淆。\n2. 修改 subject_stype.val(data[i].subject_stype) 和 subject_scontent.val(data[i].subject_scontent) 为 $(\"#th\").val(data[i].subject_stype) 和 $(\"#tmmc\").val(data[i].subject_scontent)，以正确设置表单元素的值。\n\n修改后的代码如下：\n\njavascript\nlet vote_vid = 0;\n$(\"#tjwt\").click(function () {\n var subject_stype_val = $(\"#th\").val();\n var subject_scontent_val = $(\"#tmmc\").val();\n $.ajax({\n url: \"/getSubject\",\n type: \"get\",\n dataType: \"json\",\n data: {\n vote_vid: vote_vid,\n subject_stype: subject_stype_val,\n subject_scontent: subject_scontent_val\n },\n success: function (data) {\n for (let i = 0; i < data.length; i++) {\n $(\"#th\").val(data[i].subject_stype);\n $(\"#tmmc\").val(data[i].subject_scontent);\n }\n }\n });\n});\n