\u7b80\u5355\u7684\u601d\u8def\u662f\uff0c\u5148\u5c06\u6bcf\u7f50\u9152\u7684\u7f8e\u5473\u7a0b\u5ea6di\u4e0e\u635f\u5931\u7a0b\u5ea6li\u7ec4\u5408\u6210\u4e00\u4e2a\u4e8c\u5143\u7ec4\uff08di\uff0cli\uff09\uff0c\u7136\u540e\u6309\u7167di\u4ece\u5927\u5230\u5c0f\u7684\u987a\u5e8f\u5bf9\u4e8c\u5143\u7ec4\u8fdb\u884c\u6392\u5e8f\u3002\u7136\u540e\uff0c\u5c06\u9152\u7f50\u76d8\u76d8\u4ece1\u5230N\u8fdb\u884c\u7f16\u53f7\uff0c\u518d\u5c06\u6392\u5e8f\u540e\u7684\u4e8c\u5143\u7ec4\u4e0e\u9152\u7f50\u76d8\u76d8\u4e00\u4e00\u5bf9\u5e94\uff0c\u5c31\u53ef\u4ee5\u5f97\u5230\u6bcf\u7f50\u9152\u76d8\u76d8\u7684\u7f16\u53f7\u3002\n\n\u5177\u4f53\u5b9e\u73b0\u6b65\u9aa4\u5982\u4e0b\uff1a\n1\uff0e\u8bfb\u53d6\u8f93\u5165\u7684N\uff0cd\u6570\u7ec4\u548cl\u6570\u7ec4\u3002\n2\uff0e\u521b\u5efa\u4e00\u4e2a\u65b0\u7684\u4e8c\u5143\u7ec4\u6570\u7ec4comb\uff0c\u5c06d\u6570\u7ec4\u548cl\u6570\u7ec4\u6309\u7167\u7d22\u5f15\u4e00\u4e00\u5bf9\u5e94\u5730\u7ec4\u5408\u6210\u4e8c\u5143\u7ec4\uff0c\u5e76\u5c06\u4e8c\u5143\u7ec4\u5b58\u5165comb\u6570\u7ec4\u3002\n3\uff0e\u5bf9comb\u6570\u7ec4\u6309\u7167di\u4ece\u5927\u5230\u5c0f\u7684\u987a\u5e8f\u8fdb\u884c\u6392\u5e8f\u3002\n4\uff0e\u521b\u5efa\u4e00\u4e2a\u957f\u5ea6\u4e3aN\u7684\u6574\u6570\u6570\u7ec4cover\uff0c\u7528\u4e8e\u5b58\u50a8\u6bcf\u7f50\u9152\u76d8\u76d8\u7684\u7f16\u53f7\u3002\n5\uff0e\u521d\u59cb\u5316\u4e00\u4e2a\u53d8\u91cfnum\u4e3a1\uff0c\u8868\u793a\u73b0\u5728\u53ef\u7528\u7684\u9152\u7f50\u76d8\u76d8\u7f16\u53f7\u3002\n6\uff0e\u901a\u8fc7\u6392\u5e8f\u540e\u7684comb\u6570\u7ec4\uff0c\u5bf9\u4e8e\u6bcf\u4e2a\u4e8c\u5143\u7ec4\uff08di\uff0cli\uff09\uff0c\u5c06cover\u6570\u7ec4\u4e2ddi\u5bf9\u5e94\u7684\u4f4d\u7f6e\u7684\u5143\u7d20\u8d4b\u503c\u4e3a\u4e3anum\uff0c\u7136\u540e\u5c06\u4e3anum\u52a01\u3002\n7\uff0e\u8f93\u51facover\u6570\u7ec4\u3002\n\n\u5b9e\u73b0\u4ee3\u7801\u5982\u4e0b\uff1a\n\n```pythonN = int(input())d = list(map(int, input().split()))l = list(map(int, input().split()))

构建二元组数组comb = [(d[i], l[i]) for i in range(N)]# 按照di从大到小排序comb.sort(reverse=True)

cover = [0] * Nnum = 1

for i in range(N): di, li = comb[i] cover[di-1] = num num += 1

for i in range(N): print(cover[i])\n\n\u8f93\u5165\u4f8b\u5b50\u89e3\u91ca\uff1a\n\u8f93\u5165\u7684N\u4e3a5\uff0cd\u6570\u7ec4\u4e3a[10\uff0c15\uff0c6\uff0c8\uff0c9]\uff0cl\u6570\u7ec4\u4e3a[1\uff0c4\uff0c3\uff0c10\uff0c5]\u3002\n\u6309\u7167\u6b65\u9aa4\u8fdb\u884c\u8ba1\u7b97\uff0c\u6700\u540e\u5f97\u5230cover\u6570\u7ec4\u4e3a[5\uff0c4\uff0c1\uff0c3\uff0c2]\uff0c\u5c31\u662f\u7b2c1\u7f50\u9152\u5339\u914d\u4e86\u7b2c5\u4e2a\u76d8\u76d8\uff0c\u7b2c2\u7f50\u9152\u5339\u914d\u4e86\u7b2c4\u4e2a\u76d8\u76d8\uff0c\u4ee5\u6b64\u7c7b\u63a8\u3002