C++ 计算 1!+2!+...+n! 的和 (1 ≤ n ≤ 100)

#include using namespace std;

int main() { int n; cin >> n;

int sum = 0;
int fact = 1;

for (int i = 1; i <= n; i++) {
    fact *= i;
    sum += fact;
}

cout << sum << endl;

return 0;

}