Python 函数实现浮点数的整数次幂计算 (保留6位小数)

def my_power(x, n):
    result = 1.0
    if n >= 0:
        for i in range(n):
            result *= x
    else:
        for i in range(-n):
            result /= x
    return round(result, 6)

print(my_power(3.14, -2))

输出结果为：0.101424