C语言实现字符串回文判断：修复代码示例与解析

{/'title/':/'C语言实现字符串回文判断：修复代码示例与解析/',/'description/':/'本文提供了一个使用C语言实现判断字符串是否为回文的示例代码，并对代码进行了详细的修复和解析，包括栈结构的定义、操作函数的改进以及输入输出方式的优化。/',/'keywords/':/'C语言, 字符串, 回文, 栈, 数据结构, 代码修复, 解析, 示例/',/'content/':/'#include ///'stdio.h///'//n#include ///'stdbool.h///'//n#include ///'string.h///'//n//n#define MAX_SIZE 20//n//ntypedef char elem;//n//ntypedef struct {//n elem data[MAX_SIZE];//n int top;//n} sqstack;//n//nvoid initstack(sqstack *st) {//n st->top = -1;//n}//n//nbool isempty(sqstack *st) {//n return st->top == -1;//n}//n//nbool isfull(sqstack *st) {//n return st->top == MAX_SIZE - 1;//n}//n//nbool pushstack(sqstack *st, elem e) {//n if (isfull(st)) {//n return false;//n }//n st->data[++st->top] = e;//n return true;//n}//n//nbool popstack(sqstack *st, elem *e) {//n if (isempty(st)) {//n return false;//n }//n *e = st->data[st->top--];//n return true;//n}//n//nvoid destroystack(sqstack *st) {//n st->top = -1;//n}//n//nbool symmetry(elem str[]) {//n int i;//n elem e;//n sqstack st;//n char prompt1[] = /'please input string for judge: /';//n printf(/'%s/', prompt1);//n gets(str);//n initstack(&st);//n for (i = 0; str[i] != '//0'; i++) {//n pushstack(&st, str[i]);//n }//n for (i = 0; str[i] != '//0'; i++) {//n popstack(&st, &e);//n if (str[i] != e) {//n destroystack(&st);//n printf(/'is not sym//n/');//n return false;//n }//n }//n destroystack(&st);//n printf(/'is sym//n/');//n return true;//n}//n//nint main() {//n elem str[MAX_SIZE];//n symmetry(str);//n return 0;//n}/