Python Matplotlib 绘制曲线 y1=0.2e^(-0.5x)cos(2πx) 和 y2=2e^(-0.5x)cos(πx) 图形

import numpy as np import matplotlib.pyplot as plt

x = np.linspace(0, 2np.pi, 100) y1 = 0.2np.exp(-0.5x)np.cos(2np.pix) y2 = 2np.exp(-0.5x)np.cos(np.pix)

plt.plot(x, y1, color='blue', linestyle='-', label='y1=0.2e^(-0.5x)cos(2πx)') plt.plot(x, y2, color='red', linestyle='--', label='y2=2e^(-0.5x)cos(πx)')

plt.title('Graph of y1 and y2') plt.xlabel('x') plt.ylabel('y') plt.text(2, 1, 'y1=0.2e^(-0.5x)cos(2πx)', fontsize=12) plt.text(2, -1.5, 'y2=2e^(-0.5x)cos(πx)', fontsize=12) plt.legend() plt.grid(True)

plt.show()