C++代码优化：计算x=a/b并打印接近0.000001的值

int a = -1, b = 1; float x = 1.0f, sum; for (int i = 0; x >= 0.000001 || x <= -0.000001; i++) { a *= a; x = a / (float)b; b += 2; if (abs(x - 0.000001) <= 0.000001) cout << x << endl; }