Python 代码：将嵌套列表转换为两个独立列表

data = [[('a', 'b', 'c', 'd'), ('a', 'e')], [(1, 2, 3, 4), (1, 5)], [(5, 6, 7, 8), (5, 5)], [(11, 22, 33, 44), (11, 88)], [(33, 55, 66, 77), (33, 87)], [(12, 34, 43, 44), (12, 22)], [(12, 65, 87, 14), (12, 11)], [(12, 33, 56, 12), (12, 32)], [(44, 54, 22, 15), (44, 43)], [(87, 76, 98, 53), (87, 44)], [(27, 92, 14, 65), (27, 53)]]

list1 = [] list2 = []

for sublist in data: list1.append(sublist[0]) list2.append(sublist[1])

result1 = [tuple(i) for i in list1] result2 = [tuple(i) for i in list2]

print(result1) print(result2)