C++ 求解指定范围内奇数之和

#include using namespace std;

int main() { int m, n; cin >> m >> n;

int sum = 0;
for (int i = m; i <= n; i++) {
    if (i % 2 != 0) {
        sum += i;
    }
}

cout << sum << endl;

return 0;

}