Probability of Not Rolling a Six in Three Dice Throws

To find the probability of not rolling a six in a single throw of a fair die, we need to determine the number of favorable outcomes (rolling any number other than six) divided by the total number of possible outcomes (rolling any number from one to six). \n\nThe number of favorable outcomes is 5 (rolling numbers 1, 2, 3, 4, or 5), and the total number of possible outcomes is 6.\n\nTherefore, the probability of not rolling a six in a single throw is 5/6.\n\nTo find the probability of not rolling a six in three throws, we need to multiply the probabilities of not rolling a six in each individual throw.\n\n(5/6) * (5/6) * (5/6) = 125/216 ≈ 0.5792\n\nTherefore, the probability for rolling no six in three throws of a fair die is approximately 0.5792.\n\nThe correct answer is C: 0.5792.