C++ Solution for Jump Game: Dynamic Programming Approach

The given code is a solution to the Jump Game problem.

The function 'canJump' takes in a vector of integers 'nums', which represents the maximum number of steps that can be taken at each position in the array. The goal is to determine if it is possible to reach the last position in the array.

The code initializes an array 'dp' of the same size as 'nums'. This array is used to keep track of whether a particular position in 'nums' is reachable or not. Initially, all elements in 'dp' are set to 0.

The first for loop iterates through all positions in 'nums' except the last position. For each position 'i', it sets the corresponding element in 'dp' to 0.

The second for loop iterates through all positions in 'nums' except the last position again. For each position 'i', it checks all positions that can be reached from 'i' (i.e. positions from 'i+nums[i]' to 'i'). If any of these positions is reachable (i.e. 'dp[t]' is non-zero), it breaks out of the loop. Otherwise, it sets 'dp[t]' to 1 to mark it as reachable.

After the second for loop, it checks if the last position in 'dp' is reachable (i.e. 'dp[nums.size()-1]' is non-zero). If it is, it returns true indicating that it is possible to reach the last position. Otherwise, it returns false indicating that it is not possible to reach the last position.

Overall, the code uses dynamic programming to keep track of reachable positions and checks if the last position is reachable.