C Programming: Understanding Logical Operators and Increment Operators

The output of the code is:
x=1 y=0
x=2 y = 0\

Explanation:\

• In the first line, the expression !x || y++ is evaluated. The !x returns 0 (false) since x is 1, so the y++ part is not executed. Therefore, the value of x and y remain unchanged.\
• In the second line, the expression !y && ++x is evaluated. The !y returns 1 (true) since y is 0, so the ++x part is executed and x becomes 2. Therefore, x is incremented and y remains unchanged.