C++ 编程:构造满足特定条件的序列
#include
int main() { int x; cin >> x;
while (x--) {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
a[i] = i + 1;
}
int sum = 0;
for (int i = 0; i < n; i++) {
sum += a[i];
}
int k = sum / n;
for (int i = 0; i < n; i++) {
a[i] *= k;
}
for (int i = 0; i < n; i++) {
cout << a[i] << " ";
}
cout << endl;
}
return 0;
}
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