写一个C++代码：身份证号码n题目描述n十八位居民身份证号码由-6-位地址码、8-位出生日期码、3-位顺序码和-1-位校验码组成倒数第-2-位是性别代码男单女双其格式如图所示。nn1644118823476158398pngn其中校验码的计算方法如下：n1将身份证号码的前-17-位数字分别乘以对应的系数对应关系如下表。-nn号码位nn1nn2nn3nn4nn5nn6nn7nn8nn9nn10nn11nn12nn13nn14nn15nn16nn17nn系数nn7nn9nn10nn5nn8nn4nn

#include #include using namespace std;

int main() { string id; cin >> id;

// 验证身份证号码是否为18位数字
if (id.size() != 18)
{
    cout << "wrong!" << endl;
    return 0;
}
for (int i = 0; i < 18; i++)
{
    if (id[i] < '0' || id[i] > '9')
    {
        cout << "wrong!" << endl;
        return 0;
    }
}

// 计算校验码
int factors[17] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
int sum = 0;
for (int i = 0; i < 17; i++)
{
    sum += (id[i] - '0') * factors[i];
}
int remain = sum % 11;
char checkCode;
switch (remain)
{
    case 0:
        checkCode = '1';
        break;
    case 1:
        checkCode = '0';
        break;
    case 2:
        checkCode = 'X';
        break;
    case 3:
        checkCode = '9';
        break;
    case 4:
        checkCode = '8';
        break;
    case 5:
        checkCode = '7';
        break;
    case 6:
        checkCode = '6';
        break;
    case 7:
        checkCode = '5';
        break;
    case 8:
        checkCode = '4';
        break;
    case 9:
        checkCode = '3';
        break;
    case 10:
        checkCode = '2';
        break;
}
if (checkCode != id[17])
{
    cout << "wrong!" << endl;
    return 0;
}

// 解析出生日期和性别
string address = id.substr(0, 6);
string year = id.substr(6, 4);
string month = id.substr(10, 2);
string day = id.substr(12, 2);
string genderCode = id.substr(16, 1);
string gender;
if (stoi(genderCode) % 2 == 1)
{
    gender = "male";
}
else
{
    gender = "female";
}

// 输出结果
cout << year << "-" << month << "-" << day << "," << gender << endl;

return 0;

}