Int and Double Type Operations: Why the Result is Always Double

This is because when an operation involves both an int and a double, the int is automatically converted to a double before the operation takes place. This is called type promotion.

For example, if we have the following code:

int num1 = 5; double num2 = 2.5; double result = num1 + num2;

In this case, the int value of 5 is automatically promoted to a double before the addition operation takes place. The result of the addition is also a double, which is then assigned to the variable result.

So even though one of the operands was an int, the final result is a double due to type promotion.