Code:

boolean matches = Pattern.matches("[[^dz]&&[^0-9]]5,", "abcdef");
System.out.println(matches ? "match" : "Mismatch");

Output: C - Mismatch

Explanation: The regular expression '[[^dz]&&[^0-9]]5,)' breaks down as follows:

  • '[^dz]': Matches any character except 'd' or 'z'.
  • '&&': Intersects the previous character class with the next one.
  • '[^0-9]': Matches any character that is not a digit.
  • '5': Matches the character '5' literally.
  • ',': Matches the comma character literally.
  • ')': Matches the closing parenthesis literally.

In essence, the regex searches for a string that starts with a character that is neither 'd' nor 'z' and is not a digit, followed by a '5' and a comma. The string 'abcdef' fails this test because it contains the letter 'd'. Therefore, the output is 'Mismatch'.

Java Regex Pattern Matching: Understanding '[[^dz]&&[^0-9]]5,)' and 'abcdef'

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