C++ 计算满足 x xor (2*x) xor (3*x) = 0 的整数个数

#include using namespace std;

int main() { int n, count = 0; cin >> n; for (int i = 0; i <= n; i++) { if ((i ^ (2 * i) ^ (3 * i)) == 0) { count++; } } cout << count << endl; return 0; }