Python Program to Find the 100th Prime Number

This is a Python program that counts the first 100 prime numbers and outputs the 100th prime number.

count = 0
num = 2
while True:
    for i in range(2, num):
        if num % i == 0:
            break
    else:
        count += 1
    if count < 100:
        num += 1
        continue
    print(num, '是从小到大0')
    break

Explanation:

• The program initializes two variables: count is set to 0, and num is set to 2.
• The while loop runs indefinitely until it's broken by the break statement within the if statement.
• Inside the while loop, a for loop iterates from 2 to the value of num. If any number between 2 and num (exclusive) divides num with no remainder, the if statement executes, and the loop breaks using break. If num is prime, the else statement executes, and count is incremented.
• After checking if num is prime, the program checks if count is less than 100. If it is, num is incremented by 1, and the continue statement sends the program back to the beginning of the while loop. If count is equal to or greater than 100, the program prints the value of num and a message indicating it's the 100th prime number, then breaks out of the while loop.

Note: The output message '是从小到大0' is likely an error or typo in the original code, as it doesn't make sense in either Chinese or English. It should be replaced with a proper message indicating the 100th prime number has been found.