The output of this program will be:

6 12

Explanation:

  • We declare a union called 'myun' which contains a struct with three integers 'x', 'y', and 'z', as well as a single integer 'k'.
  • In the 'main' function, we assign values to 'a.u.x', 'a.u.y', and 'a.u.z', as well as 'a.k'.
  • When we print 'a.u.x', we get the value of '6' instead of '4' because the value of 'a.k' overwrote the values of 'a.u.x', 'a.u.y', and 'a.u.z'.
  • The 'sizeof(a)' statement prints the size of the union 'a', which is '12' bytes since the 'struct' inside the union occupies 3 integers, each taking up 4 bytes.
C Union Example: Understanding Memory Overlap

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