C Programming: Swapping Variables Using Pointers

There are a few syntax errors in this code, specifically with the use of Chinese characters instead of English characters for certain symbols. Here is the corrected code:

#include <stdio.h>

int main() { int a, b, *p1, *p2, *p; a = 1; b = 2; p1 = &a; p2 = &b; if (a < b) { p = p1; p1 = p2; p2 = p; } printf('%d, %d\n', a, b); return 0; }

This code declares four integer variables ('a', 'b', '*p1', '*p2') and a pointer variable '*p'. It assigns 'a' to 1 and 'b' to 2, and then assigns the memory addresses of 'a' and 'b' to 'p1' and 'p2', respectively.

The 'if' statement checks if 'a' is less than 'b'. If it is, the pointer variables 'p1' and 'p2' are swapped using a temporary variable 'p'.

Finally, the 'printf' statement prints the values of 'a' and 'b', separated by a comma and a space. The program then returns 0 to indicate successful completion.