C++ 数组翻转：前 size 个元素反转

#include using namespace std;

const int N = 1010;

int n, size; int a[N];

void reverse(int a[], int size) { for (int i = 0, j = size - 1; i < j; i ++, j -- ) swap(a[i], a[j]); }

int main() { cin >> n >> size;

for (int i = 0; i < n; i ++ )
    cin >> a[i];

reverse(a, size);

for (int i = 0; i < n; i ++ )
    cout << a[i] << ' ';

return 0;

}