1 到 100 的连乘积：计算结果与 Python 代码

该题可以使用循环来解决，具体代码如下：

result = 1
for i in range(2, 101):
    result *= i
print(result)

输出结果为：

93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000

因此，从 1 连续乘到 100 的和是 '93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000'。