Java Regular Expression Split: Understanding the Output

Rom wrote the following regular expression program. What will be the output?

Pattern myPattern = Pattern.compile(":");
String[] split = myPattern.split("one:two:three:four:", 2);
for (String element : split) {
System.out.println("element = " + element);
}

Output:

element = one
element = two:three:four:

Explanation:

• Pattern.compile(":") - Creates a regular expression pattern that matches the colon character (':').
• myPattern.split("one:two:three:four:", 2) - Splits the input string into an array, using the colon as a delimiter. The '2' indicates the maximum number of splits to perform. This means the string will be split into at most two parts.
• For loop - Iterates over the elements of the split array and prints each element.

Key points:

• The split method will stop after it has split the input string into the specified number of parts (2 in this case).
• The remaining parts after the limit is reached are concatenated into the last element of the resulting array.

Incorrect Options:

• OA Runtime error: The code is valid Java and will execute successfully.
• OC element- one element = two element = three element = four: The code will not split the string into individual words due to the limit set on the split method.
• OD element=one element -two element = three element = four element = two:three:four: The code doesn't split the string into individual words and the last element should include the remaining parts after the limit is reached.