Python开箱游戏代码:模拟8个箱子,1个炸弹,随机位置,按键操作
以下是实现上述要求的Python代码:
import pygame
import random
# 初始化pygame
pygame.init()
# 设置屏幕尺寸
screen_width = 800
screen_height = 400
screen = pygame.display.set_mode((screen_width, screen_height))
# 加载图片
box_image = pygame.image.load('D:\1开箱实验\开箱实验_8平衡\正式实验\zsPic\box.png')
gold_image = pygame.image.load('D:\1开箱实验\开箱实验_8平衡\正式实验\zsPic\gold.png')
bomb_image = pygame.image.load('D:\1开箱实验\开箱实验_8平衡\正式实验\zsPic\bomb3.png')
# 缩小图片
box_image = pygame.transform.scale(box_image, (int(box_image.get_width() / 12), int(box_image.get_height() / 12)))
gold_image = pygame.transform.scale(gold_image, (int(gold_image.get_width() / 12), int(gold_image.get_height() / 12)))
bomb_image = pygame.transform.scale(bomb_image, (int(bomb_image.get_width() / 12), int(bomb_image.get_height() / 12)))
# 设置箱子和图片的间隔
spacing = 100
# 设置金币和炸弹的数量
num_gold = 7
num_bomb = 1
# 设置每一轮的箱子位置
round_positions = [[spacing * i + (screen_width - (spacing * 8)) / 2, (screen_height - box_image.get_height()) / 2] for i in range(8)]
# 游戏循环
for _ in range(5):
# 随机确定炸弹位置
bomb_index = random.randint(0, 7)
# 打开的箱子数量
opened_boxes = 0
# 获得的金币数量
gold_collected = 0
while True:
# 处理事件
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_w: # 按下w键,打开箱子
opened_boxes += 1
if opened_boxes == bomb_index + 1: # 打开的箱子是炸弹
screen.blit(bomb_image, round_positions[bomb_index])
pygame.display.update()
pygame.time.wait(1000)
pygame.quit()
quit()
else: # 打开的箱子是金币
screen.blit(gold_image, round_positions[opened_boxes-1])
pygame.display.update()
gold_collected += 1
if gold_collected == num_gold: # 所有金币都获得完毕
pygame.quit()
quit()
if event.key == pygame.K_p: # 按下p键,停止打开箱子
pygame.quit()
quit()
# 绘制箱子
for i in range(opened_boxes):
screen.blit(box_image, round_positions[i])
pygame.display.update()
请注意,上述代码需要先安装并导入Pygame模块,可以通过执行pip install pygame来安装Pygame。此外,代码中加载图片的路径需要根据实际情况进行修改。
原文地址: https://www.cveoy.top/t/topic/o9bB 著作权归作者所有。请勿转载和采集!