用 MATLAB 计算 π 的近似值：循环实现公式 π^2/6 = 1/1^2 + 1/2^2 + 1/3^2 + ... + 1/n^2

clear clc n = [100, 1000, 10000]; for i = 1:length(n) sum = 0; for j = 1:n(i) sum = sum + 1/j^2; end pi_approx = sqrt(6*sum); disp(['n = ', num2str(n(i)), ', pi approx = ', num2str(pi_approx)]) end