C语言计算三个数的平均值 (保留6位小数)

#include <stdio.h>

int main() { double num1, num2, num3; double average;

printf('请输入三个数：');
scanf('%lf %lf %lf', &num1, &num2, &num3);

average = (num1 + num2 + num3) / 3;

printf('它们的平均数为：%.6lf\n', average);

return 0;

}