Python代码：判断简单加法算式个数

n = int(input()) count = 0 for i in range(n-2): a = i b = i + 1 c = i + 2 if a%10 + b%10 + c%10 < 10 and a//10%10 + b//10%10 + c//10%10 < 10 and a//100 + b//100 + c//100 < 10: count += 1 print(count)