Python 矩阵旋转90度 - 顺序赋值及格式化输出

n = int(input()) lst = [[0]*n for _ in range(n)] num = 1 for i in range(n): for j in range(n): lst[i][j] = num num += 1 for i in range(n): for j in range(n): print('{:>4d}'.format(lst[n-1-j][i]), end='') print()