BLE-Mesh 网络最佳路径算法代码实现 (Dijkstra 算法)
由于 BLE-Mesh 是一种基于广播的网络拓扑结构,因此在 BLE-Mesh 网络中,最佳路径算法通常使用 Dijkstra 算法或 A* 算法。以下是基于 Dijkstra 算法的 BLE-Mesh 最佳路径算法的代码实现。
- 定义节点类
class Node:
def __init__(self, identifier):
self.identifier = identifier
self.adjacent_nodes = {}
self.distance = float('inf')
self.visited = False
self.previous = None
def add_neighbor(self, neighbor, distance):
self.adjacent_nodes[neighbor] = distance
- 定义 BLE-Mesh 网络类
class MeshNetwork:
def __init__(self):
self.nodes = {}
def add_node(self, identifier):
self.nodes[identifier] = Node(identifier)
def get_node(self, identifier):
return self.nodes.get(identifier)
def add_edge(self, node1, node2, distance):
self.nodes[node1].add_neighbor(self.nodes[node2], distance)
self.nodes[node2].add_neighbor(self.nodes[node1], distance)
- 实现 Dijkstra 算法
import heapq
def dijkstra(mesh_network, start_node_identifier):
start_node = mesh_network.get_node(start_node_identifier)
start_node.distance = 0
heap = [(0, start_node)]
while heap:
current_distance, current_node = heapq.heappop(heap)
current_node.visited = True
for neighbor, distance in current_node.adjacent_nodes.items():
if not neighbor.visited:
new_distance = current_distance + distance
if new_distance < neighbor.distance:
neighbor.distance = new_distance
neighbor.previous = current_node
heapq.heappush(heap, (new_distance, neighbor))
- 获取最佳路径
def get_shortest_path(mesh_network, end_node_identifier):
end_node = mesh_network.get_node(end_node_identifier)
path = []
current_node = end_node
while current_node:
path.append(current_node.identifier)
current_node = current_node.previous
return path[::-1]
- 示例代码
mesh_network = MeshNetwork()
mesh_network.add_node('A')
mesh_network.add_node('B')
mesh_network.add_node('C')
mesh_network.add_node('D')
mesh_network.add_node('E')
mesh_network.add_edge('A', 'B', 1)
mesh_network.add_edge('A', 'C', 4)
mesh_network.add_edge('B', 'C', 2)
mesh_network.add_edge('B', 'D', 5)
mesh_network.add_edge('C', 'D', 1)
mesh_network.add_edge('C', 'E', 6)
mesh_network.add_edge('D', 'E', 2)
dijkstra(mesh_network, 'A')
print(get_shortest_path(mesh_network, 'E')) # Output: ['A', 'B', 'C', 'D', 'E']
原文地址: https://www.cveoy.top/t/topic/nVP3 著作权归作者所有。请勿转载和采集!