def count_and_sort(s): d = {} for c in s: if c in d: d[c] += 1 else: d[c] = 1 items = list(d.items()) items.sort(key=lambda x: (-x[1], ord(x[0]))) # 按照统计个数和ASCI码排序 result = '' for item in items: result += item[0] * item[1] return result

输入字符串

s = input('请输入字符串：')

输出排序后的字符串

print(count_and_sort(s))