Python 剪刀石头布游戏代码：简单易懂，随机出拳，胜负判断

import random

print('剪刀石头布游戏开始！')
print('请输入1代表剪刀，2代表石头，3代表布，输入0结束游戏。')

while True:
    player = int(input('请出拳：'))
    if player == 0:
        print('游戏结束，谢谢参与！')
        break
    elif player not in [1, 2, 3]:
        print('请正确输入！')
        continue

    computer = random.randint(1, 3)

    print('玩家出的是：', end='')
    if player == 1:
        print('剪刀')
    elif player == 2:
        print('石头')
    else:
        print('布')

    print('电脑出的是：', end='')
    if computer == 1:
        print('剪刀')
    elif computer == 2:
        print('石头')
    else:
        print('布')

    if player == computer:
        print('平局！')
    elif (player == 1 and computer == 3) or \
         (player == 2 and computer == 1) or \
         (player == 3 and computer == 2):
        print('你赢了！')
    else:
        print('你输了！')

该代码使用 random.randint(1, 3) 函数生成电脑出拳的随机数，分别代表剪刀、石头、布。使用条件判断语句判断胜负，输出对应的结果。